1.

Car travelling along a straight road at 14m/s is approaching traffic lights .driver applies brakes and car comes to rest with constant retardation/deceleration. The distance from the point where brakes are applied to where the car comes to rest is 49 m. Find deceleration.

Answer»

INITIAL velocity=14m/s

Final velocity=0m/s

Distance travelled=49m

we know,

{v}^{2}   =  {u}^{2}  + 2as

0=14^2+2*49a

a=-196/98

a=-2m/s/s

Deceleration=2m PER SECOND per second.



Discussion

No Comment Found

Related InterviewSolutions