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Carbon occur in nature as a mixture of `C-12` and `C-13`. Average atomic mass of carbon is `12.011` what is the `%` abundance of `C-12` in nature ?A. `98.9%`B. `60.9%`C. `32.9%`D. `1.4%` |
Answer» Correct Answer - 1 `{:("Isotopes of carbon",,C^(12),,C^(13)),(% " of abundance",=,x%,,(100-x)%):}` Average atomic mass `=(x xx12)/(100)+((100-x)xx13)/(100)` `12.011=(12x)/(100)+(1300-13x)/(100)` `12.011=(12x+1300-13x)/(100)=(-x+1300)/(100)` `12.011=(-x+1300)/(100)` `-x+1300=1201.1` `-x=12.011-1300` `-x=-98.9` `x=98.9%` `:. C^(12)=98.9%` `C^(13)=1.1%` |
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