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Cards bearing numbers 2, 4, 6, 8, 10, 12, 14, 16, 18 and 20 are kept in a bag. A card is drawn at random from the bag. Find the probability of getting a card which is : (i) a prime number. (ii) a number divisible by 4. (iii) a number that is a multiple of 6. (iv) an odd number. |
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Answer» Total number of cards in the bag = 10 (i) Total prime numbers = 1 i.e., 2 ∴ Required Probability = 1/10 (ii) Total numbers divisible by 4 = 5 (i.e., 4, 8, 12, 16, 20] Required Probability = 5/10 =1/2 (iii) Total numbers divisible by 6 or multiple of 6 = 3 [i.e., 6, 12, 18] ∴ Required Probability = 3/10 (iv) Total odd number = 0 ∴ Required Probability = 0/10= 0. |
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