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CAREER INSTITUTEA mixture of pure AgCl and AgBr is found to have 60.94% Ag by mass. What are the mass % of Cl and Br in the mixture.43 904 oand its molecular weight is 146, Deduce its27, |
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Answer» The fraction of silver in each of the compounds is: Ag/AgCl = 0.7529 Ag/AgBr = 0.5746 The fraction of silver in the mixed sample is 0.6094 therefore, if we let x = the fraction of the sample that is AgCl and (1-x) is the fraction of the sample that is AgBr, then: x(0.7529) + (1-x)(0.5746) = 0.6094 Solving for x: x = 0.1949 or 19.49% AgCl in the sample. |
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