CB[CB2. Find the zeros of the polynomial x +x-plp+ 1).

1.	CB[CB2. Find the zeros of the polynomial x +x-plp+ 1).
Answer» x² + x - p(p+1) = x² + (p +1)x - px - p(p +1) = x(x + p + 1) - p(x + p + 1) = (x + p + 1)(x - p)To find the zeroes, equate the factors to zero. x + p + 1 = 0=> x = -p -1 x - p = 0=> x = p Therefore, zeroes are -p -1, p

Answer»

x² + x - p(p+1) = x² + (p +1)x - px - p(p +1) = x(x + p + 1) - p(x + p + 1) = (x + p + 1)(x - p)To find the zeroes, equate the factors to zero. x + p + 1 = 0=> x = -p -1

x - p = 0=> x = p

Therefore, zeroes are -p -1, p

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CB[CB2. Find the zeros of the polynomial x +x-plp+ 1).

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