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[CBSE (D) 2010)1. Find the zeroes of the following quadraticpolynomial and verify the relationship between zeroesand their coefficient :(1) 372x2 + 13x + 62 (ii) 415x2 – 17x – 3/5[CBSE Sept. 2010]. 11of the |
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Answer» 3√2 x² + 13 x + 6√2= 3√2 x² + 9x + 4x + 6√2= 3x(√2 x + 3) + 2√2(√2x + 3)= (√2x + 3)(3x + 2√2) Zeroes of the polynomial:(3x + 2√2) = 0⇒ x =2√2/3(√2x + 3) = 0⇒ x =-3/√2Sum of the roots = 2√2/3 -3/√2 = -13/3√2Product of the roots = 2√2/3 × 3/√2 = 2 Sum of the roots = -b/a = -13/3√2Product of the roots = c/a = 6√2 / 3√2 = 2. 3√2x^2 + 13 X +6√2. = 3√2x^2+9x + 4x + 6√2. =3x( V2x +3)+ 2V2( V2x +3) (3x + 2V2)( V2x + 3); 3x = -2V2; x = -2V2/3; V2x = -3; x = -3/-V2 = 3/V2 |
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