`CDCl_(3)` is extensively used as a solvent for scanning NMR spectra. How can it be prepared from `CHCl_(3)` ?

`CDCl_(3)` is extensively used as a solvent for scanning NMR spectra.

1.	`CDCl_(3)` is extensively used as a solvent for scanning NMR spectra. How can it be prepared from `CHCl_(3)` ?
Answer» Due to -I-effect of the three Cl atoms, the atoms, the electron density in the C-H bond decreases. In other words, hydrogen in `CHCl_(3)` is slightly acidic and thus can be easily abstracted by a strong base such as `OH^(-)` to form `""^(-)"CC"l_(3)` which then reacts with `D_(2)O` to form `CDCl_(3)` `underset("Chloroform")(Hto "CC"l_(3)) underset(-H_(2)O)overset(OH^(-))to `""_(-):"CC"l_(3)overset(D_(2)O) to underset("Chloroform")underset("Deuterated")(CDCl_(3))+ DOH`

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`CDCl_(3)` is extensively used as a solvent for scanning NMR spectra. How can it be prepared from `CHCl_(3)` ?

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