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`Ce^(4+)` is stable .This is because ofA. half-filled d-orbitalB. all paired electrons in d-orbitalC. empty orbitalD. fully filled d-orbital |
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Answer» Correct Answer - C The electronic configuration of Ce is `Ce_(58)=[Xe]4f^(1)5d^(1)6s^(2)` (predicted) or `=[Xe]4f^(2)5d^(0)6s^(2)` (observed) `Ce^(4+)=[Xe]4f^(0)5d^(0)6s^(0)` Since, in `+4` oxidation state, all 4f,5d and 6s orbitals are empty and Ce gains the stable configuration of nearest inert gas . Hence, `Ce^(4+)` is most stable . |
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