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Centre at (0, 0), major axis on the y-axis and passes through the points (3, 2) and (1, 6). |
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Answer» Major axis lie on the y-axis so the standard equation of the ellipse is of the form \(\frac{x^2}{a^2}+ \frac{y^2}{b^2} = 1\) Since the ellipse passes through (3, 2) \(\frac{9}{a^2} + \frac{4}{b^2} = 1\) .........(1) Since the ellipse passes through (1, 6) \(\frac{1}{a^2} + \frac{36}{b^2} = 1\) ......... (2) Solving (1) and (2), we have Since the ellipse passes through (3, 2) a2 = 40; b2 = 10 Thus the equation of the ellipse is \(\frac{x^2}{40}+ \frac{y^2}{10}\)= 1 |
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