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Ceratain radioactive substance reduces to `25%` of its value is `16 days`. Its half-life isA. 32 daysB. 8 daysC. 64 daysD. 28 days |
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Answer» Correct Answer - B We have, `N=No((1)/(2))^(t//T)implies(N_(0))/(4)=N_(0)((1)/(2))^(16//T)impliesT=` 8 days |
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