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Certain amount of a gas at 25^@C and 76cm Hg occupies volume of 12.0L. What will be the pressure at a height where temperature is 10^@C and volume is 12.8L? |
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Answer» Solution :Equation of STATE is given as, `(P_(1)V_(1))/(T_(1)) = (P_(2)V_(2))/(T_(2))` `P_(1) = 76CM Hg, P_(2) = ? , V_(1) = 12.0L, V_(2) = 12.8L, T_(1) = 298K, T_(2) = 283K` The PRESSURE at the given HEIGHT ` = P_(2) = (P_(1)V_(1))/(T_(1)) xx (T_(2))/(V_(2)) = (76 xx 12 xx 283)/(12.8 xx 298) = 67.66 ` cm Hg |
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