Cesium atoms are the largest neturally occurring atoms. The radius of `Cs` atom is `2.6 Å`. The number of moles of `Cs` atoms to be laid side by side to give a row of `Cs` atoms `2.5 cm` long is `x xx 10^(-17)`. Find the value of `x`.

Cesium atoms are the largest neturally occurring atoms. The radius of

1.	Cesium atoms are the largest neturally occurring atoms. The radius of `Cs` atom is `2.6 Å`. The number of moles of `Cs` atoms to be laid side by side to give a row of `Cs` atoms `2.5 cm` long is `x xx 10^(-17)`. Find the value of `x`.
Answer» Correct Answer - 8 Diameter of Cs= `2xx2.6=5.2overset(@)A=5.2xx10^(-8)cm` Number of atoms in 2.50cm row= `(2.50)/(5.2xx10^(-8))=0.48xx10^(8)=4.8xx10^(7)`Cs atoms `therefore` Moles of Cs atoms= `(4.8xx10^(7))/(6xx10^(23))=0.8xx10^(-16)=8xx10^(-17)` `therefore xxx10^(-17)=8xx10^(-17)rArrx=8`

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Cesium atoms are the largest neturally occurring atoms. The radius of `Cs` atom is `2.6 Å`. The number of moles of `Cs` atoms to be laid side by side to give a row of `Cs` atoms `2.5 cm` long is `x xx 10^(-17)`. Find the value of `x`.

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