CH_2 = C=CH_2 underset((2) H^(oplus))overset((1) Na// NH_3(l))to (P) underset("(Fe) tube")overset("Red hot ")to (Q) Compound 'P' can give white ppt with ammonical silver nitrate, and compound 'Q' is thermodynamically more stable among its position isomers, now maximum number of atoms in "Q" that are in one plane in any possible conformation are x, then find x – 3y? Where 'y' is number of position isomers of (Q)

CH_2 = C=CH_2 underset((2) H^(oplus))overset((1) Na// NH_3(l))to (P) u

1.	CH_2 = C=CH_2 underset((2) H^(oplus))overset((1) Na// NH_3(l))to (P) underset("(Fe) tube")overset("Red hot ")to (Q) Compound 'P' can give white ppt with ammonical silver nitrate, and compound 'Q' is thermodynamically more stable among its position isomers, now maximum number of atoms in "Q" that are in one plane in any possible conformation are x, then find x – 3y? Where 'y' is number of position isomers of (Q)
Answer» SOLUTION : So = x-3y = 15-3 `XX` 2 = 9