1.

CH_(2)=CH-CH_(2)-CH_(2)-C-=CH underset((1 eq))overset(HBr)toProduct is

Answer»

`BrCH_(2)-CH_(2)-CH_(2)-CH_(2)-C-=CH`
`CH_(2)=CH-CH_(2)-CH_(2)-CH=CH-Br`
`CH_(2)=CH-CH_(2)-CH_(2)-UNDERSET(Br)underset(|)C=CH_(2)`
`CH_(3)-underset(Br)underset(|)CH-CH_(2)-CH_(2)-C-=CH`

Answer :D


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