CH_2 = CH - CH = underset(CH_3)underset(|)C-CH_3 overset(+HBr)to CH_3-overset(Br)overset(|)CH-CH = underset(CH_3)underset(|)C-CH_3 + underset((II))(CH_3 - CH ) = CH - underset(CH_3)underset(|)overset(Br)overset(|)C-CH_3 Correct statement about the above reaction is

CH_2 = CH - CH = underset(CH_3)underset(|)C-CH_3 overset(+HBr)to CH_3-

1.	CH_2 = CH - CH = underset(CH_3)underset(\|)C-CH_3 overset(+HBr)to CH_3-overset(Br)overset(\|)CH-CH = underset(CH_3)underset(\|)C-CH_3 + underset((II))(CH_3 - CH ) = CH - underset(CH_3)underset(\|)overset(Br)overset(\|)C-CH_3 Correct statement about the above reaction is
Answer» 'I' is kinetic CONTROLLED PRODUCT 'II' is thermodynamic controlled product I' is major product at low TEMPERATURE 'II' is major product at low temperature Solution : Product from more stable intermediate is CALLED kinetic controlled and it is the major product at low temperature. More stable product is called thermodynamic controlled product and it is the major product at HIGH temperature.