1.

`(CH_(3))_(2)C=CHCH_(3)+NOBr rarr` Product . The structure of the product isA. `(CH_(3))_(2)C(NO)-CH(Br)CH_(3)`B. `(CH_(3))_(2)C(Br)-CH(NO)CH_(3)`C. `(CH_(3))_(2)CH-C(NO)(Br)CH_(3)`D.

Answer» Correct Answer - b
The reaction follows Markownikoff rule, namely the bromide ion adds on to the carbon having the least number of hydrogen and the more positive part namely the `-NO` group adds to the other carbon of the double bond.


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