1.

`(CH_(3))_(3)CoNa` on reaction with`CH_(3)Br` will giveA. `(CH_(3))_(3)COC(CH_(3))_(3)`B. `CH_(3)OCH_(3)`C. `CH_(3)CH_(2)OCH_(2)CH_(3)`D. `(CH_(3))_(3)COCH_(3)`

Answer» Correct Answer - D
To have teritiary alkyl-alkyl one needs sodium teritiary alkoxide and alkyl halide.


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