Saved Bookmarks
| 1. |
`(CH_(3))_(3)CoNa` on reaction with`CH_(3)Br` will giveA. `(CH_(3))_(3)COC(CH_(3))_(3)`B. `CH_(3)OCH_(3)`C. `CH_(3)CH_(2)OCH_(2)CH_(3)`D. `(CH_(3))_(3)COCH_(3)` |
|
Answer» Correct Answer - D To have teritiary alkyl-alkyl one needs sodium teritiary alkoxide and alkyl halide. |
|