CH_(3)-C -=CMgBr can be prepared by the reaction of

1.	CH_(3)-C -=CMgBr can be prepared by the reaction of
Answer» `CH_(3)-C -=C—Br` with `MgBr_(2)` `CH_(3)-C -=CH` with `MgBr_(2)` `CH_(3)-C -=CH`with KBr and Mg METAL `CH_(3)-C -=CH` with `CH_(3)MGBR` SOLUTION :

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