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`CH_(3)CH_(2)Brunderset(alc.)overset(NaCN)toCH_(3)CN` true, hence `(CH_(3))_(3)CBrunderset(alc.)overset(NaCN)toA`. Hence A is,A. `(CH_(3))_(3)C-CN`B. `(CH_(3))_(3)C-CN`C. `CH_(3)-CH=CH-CH_(3)`D. `CH_(3)-CH_(2)-CH=CH_(2)` |
Answer» Correct Answer - B CN is stronger nucliophile causesloss of HBr instead of nucleophilic substitution reaction. |
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