1.

CH_(3)COCl on reaction with hot alcoholic potash gives

Answer»

`CH_(3)COOH`
`CH_(2) = C = O`
`CH_(3)COO^(-)K^(+)`
`(CH_(3)CO)_(2)O`

Solution :`CH_(3)COCl` on reaction with hot alcoholic potash undergoes loss of `HCl` to form KETENE `CH_(2)= C = O`
`CH_(3) - COCl + KOH (alc.) overset(Delta)rarr underset("Ketene")(CH_(2) = C = O) + KCl + H_(2)O`


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