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`CH_(3)COCl` on reaction with hot alcoholic potash givesA. `CH_(3)COOH`B. `CH_(2) = C = O`C. `CH_(3)COO^(-)K^(+)`D. `(CH_(3)CO)_(2)O` |
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Answer» Correct Answer - B `CH_(3)COCl` on reaction with hot alcoholic potash undergoes loss of `HCl` to form ketene `CH_(2) = C = O` `CH_(3) - COCl + KOH (alc.) overset(Delta)rarr underset("Ketene")(CH_(2) = C = O) + KCl + H_(2)O` |
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