1.

CH_(3)COOH_((l)) + C_(2)H_(5)OH_((l))hArrCH_(3)COOC_(2)H_(5(l)) + H_(2)O_((l)) In the above reaction, one mole of each of acetic acid and alcohol are heated in the presence of little cone. H_(2)SO_(4). On equilibrium being attained

Answer»

1 mole of ETHYL acetate is formed
2 mole of ethyl acetate are formed
`1//2` mole of ethyl acetate is formed
`2//3` moles of ethyl acetate is formed

Solution :In presence of little `H_(2)SO_(4)` (as catalyst) about `2//3` mole of each of `CH_(3)COOH` and `C_(2)H_(5)OH` react to from `2//3` mole of the product at equilibrium.


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