CH_3-overset(CH_3)overset(|)CH-C -= CH overset("Excess" HBr)to A. A is

1.	CH_3-overset(CH_3)overset(\|)CH-C -= CH overset("Excess" HBr)to A. A is
Answer» `CH_3-OVERSET(CH_3)overset(\|)CH-C overset(BR)overset(\|)H-C overset(Br)overset(\|)H_2` `CH_3-overset(CH_3)overset(\|)CH-C overset(Br)overset(\|)CH= CH_2` `CH_3-overset(CH_3)overset(\|)CH-UNDERSET(Br)underset(\|)overset(Br)overset(\|)C-CH_3` SOLUTION :

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