CH_3- underset(CH_3)underset(|)C=CH_2 + HCl overset((C_6H_5CO)_2O_2)to X (major) here 'X' is

CH_3- underset(CH_3)underset(|)C=CH_2 + HCl overset((C_6H_5CO)_2O_2)to

1.	CH_3- underset(CH_3)underset(\|)C=CH_2 + HCl overset((C_6H_5CO)_2O_2)to X (major) here 'X' is
Answer» `(CH_3)_2C(CL)-CH_3` `(CH_3)_2 CHCH_2Cl` `ClCH-2-underset(CH_2Cl)underset(\|)(CH)-CH_3` `CH_3-underset(CH_2Cl)underset(\|)overset(Cl)overset(\|)C-CH_3` Solution :`CH_3-underset(CH_3)underset(\|)C=CH_2 + H - Cl to CH_3 - underset(CH_3)underset(\|)overset(Cl)overset(\|)C - CH_3`