1.

CH_3Br + CH_3CH_2Br overset(Na//"dry either")to product. Possible product in the above reaction .

Answer»

`CH_3CH_2CH`
`CH_4`
`CH_3CH_2CH_2CH_3`
`CH_2=CH_2`

SOLUTION :This REACTION FOLLOWING freedical mechanism `overset(*)(C)H_3 & CH_3 overset(*)CH_2`, are the INTERMEDIATE freeradicals
`overset(*)(C)H_3 + overset(*)CH_3 to CH_3 , overset(*)CH_3 + CH_2CH_3 to CH_3CH_2CH_3,`
`CH_3 overset(*)(C)H_2 + overset(*)(C)H_2 CH_3 toCH_3CH_2CH_2CH_3`

`CH_3 + CH_3 - CH_3 to underset((b))(CH_4) + CH_3-CH_2`


Discussion

No Comment Found