1.

CH_3underset(Br)underset(|)CH=underset(Br)underset(|)CH_2 underset( " of alc." KOH)overset("1 equivalent")to The major product is

Answer»

`CH_3CH = CHBR`
`CH_2 = CHCH_2 Br`
`CH_3underset(Br)UNDERSET(|)C=CH_2`
NONE of these

Solution :`CH_3 - underset(Br)underset(|)CH-underset(Br)underset(|)CH_2 underset (1 mol)overset(alc. KOH)to CH_3CH = CHBr`


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