1.

CH_(4(g)) + 2O_(2(g)) rarr CO_(2(g)) + 2H_2O_((l)) DeltaH = -200 K.cal, now DeltaE Cal, now DeltaE for the same process at 300 K (in K.Cal)

Answer»

`-199.8`
`-198.9`
`-190.8`
`-198.8`

ANSWER :D


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