InterviewSolution
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InterviewSolution
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Ch 6 ex 4 |
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Answer» Here, we need to draw a line AB parallel to line PQ, through point M asshown in Fig. 6.25. Now, AB || PQ and PQ || RSTherefore, AB || RS (Why?)Now, ∠ QXM + ∠ XMB = 180° (AB || PQ, Interior angles on the same side of the transversal XM)But ∠ QXM = 135°So, 135° + ∠ XMB = 180°Therefore, ∠ XMB = 45° (1)Now, ∠ BMY = ∠ MYR (AB || RS, Alternate angles)Therefore, ∠ BMY = 40° (2)Adding (1) and (2), you get∠ XMB + ∠ BMY = 45° + 40°That is, ∠ XMY = 85° First draw a line AB between PQ and RS such that AB||PQ||RS Now, prove that angle mxq + angle xmy = 180 ( angle are in same side of transversal are 180 ) .... 1 Since you know the value of angle mxq (I.e 135°), just put this in (1), You\'ll get to know the value of angle xmy |
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