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`CH-=CHoverset(NaNH_(2))to[A]overset(CH_(3)Br)to[B]`A. `CH_(2)=CH-CH=CH_(2)`B. `HC-=C-CH_(3)`C. `CH_(2)=CH-CH_(3)`D. `CH_(3)-CH_(2)-CH_(3)` |
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Answer» Correct Answer - B |
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