1.

[{:(CH(OH)COOH),(|),(CH(OH)COOH):}] on reduction with HI consumed four moles of HI. The reduction product formed is

Answer»

`CH_(3)CH_(2)CH_(2)CH_(3)`
2-Butanol
Succine ACID
Tartonic acid

Solution :`{:(CH(OH) COOH ""CH_(2)COOH),(""+ 4HI rarr "|" ""+ 2H_(2)O + 2I_(2)),(CH(OH)COOH "" CH_(2)COOH),("Succinic acid"):}`


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