CH3-CH=CH2 forms in the presence of B2H6 and 3H2O2/OH

1.	CH3-CH=CH2 forms in the presence of B2H6 and 3H2O2/OH
Answer» Answer: Of this reagent is present follow ANTI markonikav rule. Anti markonikav rule: Negative part of the reagent GOES to the carbon atom where no of hydrogen is more. ☆ H+ comes from B2H6 ☆ OH- comes from H2O2 And so the product *Propanol* is in attachment *SHARE* *KNOWLEDGE* *AND* BE *BRAINLY*!!!

Answer»

Answer:

Of this reagent is present follow ANTI markonikav rule.

Anti markonikav rule:

Negative part of the reagent GOES to the carbon atom where no of hydrogen is more.

☆ H+ comes from B2H6

☆ OH- comes from H2O2

And so the product Propanol is in attachment

SHARE KNOWLEDGE AND BE BRAINLY!!!

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