Challenge!!!Solve for x:$$\\dfrac{d}{d cosx} (sinx)$$

1.	Challenge!!!Solve for x:$$\\dfrac{d}{d cosx} (sinx)$$
Answer» Answer is cot x<br>Let u =sinx and v= cosx.....d(sinx)/d (cosx)......d(u/v)= (v du + u dv )/ v².....[ cosx × d(sin x) - sinx × d(cosx)] / (cosx)²Since, d(sin x) = cos x and d(cos x) = -sin xTherefore, [(cosx)² + (Sinx)²]/ (cosx)²= 1/ (cos x)²=(secx)²<br>Mera toh kuch or hii answer arha hai...?sec²x....<br>Not x but solve it

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