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Change in internal energy, when 4 kJ of work is done on the system and 1 kJ of heat is given out by the system, isA. `+1 kJ`B. `-5 kJ`C. `+5 kJ`D. `+3 kJ` |
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Answer» Correct Answer - D Change in internal energy is given by the relation, `DeltaE=q+w` `DeltaE=-q+w` (as heat is given out by the system) `DeltaE=-1+4` `DeltaE=+3kJ`. |
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