1.

Change in internal energy, when 4 kJ of work is done on the system and 1 kJ of heat is given out by the system, isA. `+1 kJ`B. `-5 kJ`C. `+5 kJ`D. `+3 kJ`

Answer» Correct Answer - D
Change in internal energy is given by the relation,
`DeltaE=q+w`
`DeltaE=-q+w` (as heat is given out by the system)
`DeltaE=-1+4`
`DeltaE=+3kJ`.


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