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Chapter 8 exercise 8.1 question no. 9 please tell me fast. |
| Answer» AD || BC and BD is a transversal.∴ ∠ADB = ∠CBD [ ∵ Alternate interior angles are equal]⇒ ∠ADP = ∠CBQNow, in ∆APD and ∆CQB, we haveAD = CB [Opposite sides of a parallelogram ABCD are equal]PD = QB [Given]∠ADP = ∠CBQ [Proved]∴ ∆APD ≅ ∆CQB [By SAS congruency](ii) Since, ∆APD ≅ ∆CQB [Proved]⇒ AP = CQ [By C.P.C.T.](iii) Since, AB || CD and BD is a transversal.∴ ∠ABD = ∠CDB⇒ ∠ABQ = ∠CDPNow, in ∆AQB and ∆CPD, we haveQB = PD [Given]∠ABQ = ∠CDP [Proved]AB = CD [ Y Opposite sides of a parallelogram ABCD are equal]∴ ∆AQB = ∆CPD [By SAS congruency](iv) Since, ∆AQB = ∆CPD [Proved]⇒ AQ = CP [By C.P.C.T.](v) In a quadrilateral ∆PCQ,Opposite sides are equal. [Proved]∴ ∆PCQ is a parallelogram. | |