InterviewSolution
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InterviewSolution
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Charge `q_(2)` of mass m revolves around a stationary charge `q_(1)` in a circulare orbit of radius r. The orbital periodic time of `q_(2)` would beA. `[(4 pi^(2) mr^(3))/(k q_(1)q_(2))]^(1//2)`B. `[(k q_(1) q_(2))/(4 pi^(2) mr^(3))]^(1//2)`C. `[(4 pi^(2)mr^(4))/(k q_(1) q_(2))]^(1//2)`D. `[(4 pi^(2) mr^(2))/(k q_(1) q_(2))]^(1//2)` |
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Answer» Correct Answer - A |
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