Charle's law may be expressed as

1.	Charle's law may be expressed as
Answer» <P>`(dV//dT)_(P) = K` `(dV//dT)_(P) =KT` `(dV//dT_(P) = - K//T^(2)` `V = KT` SOLUTION :ACCORDING to Charle's law, at constant pressure `V PROP T` or `V=KT` `(dV//dT)_(P)=K`

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