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Check the commutativity and associativity of each of the following binary operations: ‘*’ on Q defined by a*b = a + ab for all a,b∈Q |
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Answer» Given that * is a binary operation on Q defined by a*b = a + ab for all a,b∈Q. We know that commutative property is p*q = q*p, where * is a binary operation. Let’s check the commutativity of given binary operation: ⇒ a*b = a + ab ⇒ b*a = b + ba = b + ab ⇒ b*a≠a*b ∴ Commutative property doesn’t holds for given binary operation ‘*’ on ‘Q’. We know that associative property is (p*q)*r = p*(q*r) Let’s check the associativity of given binary operation: ⇒ (a*b)*c = (a + ab)*c ⇒ (a*b)*c = a + ab + ((a + ab)×c) ⇒ (a*b)*c = a + ab + ac + abc ...... (1) ⇒ a*(b*c) = a*(b + bc) ⇒ a*(b*c) = a + (a×(b + bc)) ⇒ a*(b*c) = a + ab + abc ...... (2) From (1) and (2) we can clearly say that associativity doesn’t hold for the binary operation ‘*’ on ‘Q’. |
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