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Check the injective and surjective of the following functions : f : Z rarr Z given by f(x) = x^2 |
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Answer» Solution :We have `f(-1) = (-1)^2 = 1` and `f(1) = 1^2 =1 ` `THEREFORE` f maps both -1 and 1 to 1 `therefore ` f is not injective Since SQUARE of an integers can.t EXIST an integer X satisfying `x^3 = -1 ` `therefore,` f is not a subjective |
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