Check the injectivity and surjectivity of the following functions: f – InterviewSolution

1.

Check the injectivity and surjectivity of the following functions: f : R → R given by f(x) = x2

Answer»

f is not injective as f(x₁) = f(x₂) ⇒ x₁= ± x₂

Range off does not contain any negative real.

Hence not surjective.

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