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Check the injectivity and surjectivity of the following functions: f : Z → Z given by f(x) = x2 |
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Answer» f is not one-one or injective as f (1) = f (-1) ⇒ 1 = -1 f is not on to or surjective as f(x) = 2 ⇒ x = √2∉ Z |
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