1.

Check whether 3 and -2 are the zeroes of the polynomial p(x) when p(x) = x2 – x – 6.

Answer»

Given polynomial p(x) = x2 – x – 6 

We have, p(3) = 32 – 3 – 6 

= 9 – 3 – 6

= 9 – 9 

= 0 and 

p(-2) = (-2)2 – (-2) – 6 

= 4 + 2 – 6 

= 6 – 6 

= 0 

We see that p(3) = 0 and p(-2) = 0 

∴ 3 and – 2 are the zeroes of the polynomial p(x).


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