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Check whether AC = BD or not. |
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Answer» AC = \(\sqrt{(6-2)^2+(7-3)^2}\) = \(\sqrt{35}\) = \(4\sqrt2{}\) BD = \(\sqrt{(3-5)^2+(6-4)^2}\) = \(\sqrt{8}\) = \(2\sqrt2{}\) AC ≠ BD |
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