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Check whether the relation R defined in the set {1,2,3,4,5,6} as R={(a,b) : b=a+1} is reflexive, symmetric or transitive. |
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Answer» SOLUTION :R={(1,2),(2,3),(3,4),(4,5),(5,6),(6,7)} Since `!= 1+1,(1,1)!in R` `therefore`R is not reflexive` `We have (2,3) in R (therefore 3 = 2+1) but `(3,2) !in R (therefore 2 !in 3+1)` ` therefore ` R is not SYMMETRIC We have `(2,3) in R` and `(3,4) in R`but `(2,4) !in R (therefore 4 != 2+1)` ` therefore` R is not TRANSITIVE |
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