1.

Chemical equilibrium is attained in a reversible reaction carried in a close container and is of dynamic nature. The value of equilibrium constant may be expressed either as K_(p)" and " K_(c) and the two are related to each other as : K_(p) =K_(c)(RT)^(Deltang) Free energy change (DeltaG) at equilibrium point is zero. The value of equilibrium constant gives the extent to which a particular reation has proceeded to attain the equilibrium . Its value gets reversed if the reaction is reversed and becomes the square root of the initial value if the reaction is divided by 2. For the reaction PCI_(3)(g)+ CI_(2) (s) hArr PCI_(5) (g) The value of k_(c) " at " 250^(@)C " is " " mol"^(-1) L^(-1). The value of k_(p) at the same temperaturewill be :

Answer»

<P>`0.61 ATM^(-1)`
`0.56 atm^(-1)`
`0.83 atm^(-1)`
`0.46 atm^(-1)`

Solution :`K_(p) =K_(c)(RT)^(Deltang) =(26 "mol" L^(-1))`
`x (0.0821 L atm K^(-1) mol^(-1) XX 523 K^(-1))`
`= 0.61 K`


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