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Chief ore of `Zn` is `ZnS`. The ore is concentrated by froth flotation process and then heated in air to convert `ZnS` to `ZnO`. ltntgt `2 ZnS + 3O_(2) rarr 2 ZnO + 2 SO_(2)`…(i) `ZnO`, thus formed is treated with dilute `H_(2) SO_(4)`. `ZnO + H_(2) SO_(4) rarr ZnSO_(4) + H_(2) O` ....(ii) On electrolysis of `ZnSO_(4(aq)), Zn` metal is produced. `2 ZnSO_(4) + H_(2) O rarr 2 Zn + 2H_(2) SO_(4) + O_(2)`....(iii) What mass of `Zn` will be obtained from an ore containing `225 kg` of `ZnS` ? `(Zn = 65, S = 32, O = 16, H = 1)`.A. 102 kgB. 151 kgC. 112 kgD. 134 kg |
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Answer» Correct Answer - B `225 xx 10^(3) of ZnS = (225 xx 10^(3))/(97)` =`2.32 xx 10^(3) mol ZnS` =`2.32 xx 10^(3) mol of Zn` =`2.32 xx 10^(3) xx 65 of Zn` =`150.8 Kg Zn ~~ 151 Kg Zn`. |
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