Chlorine gas is prepared by reaction of H_2SO_4 with MnO_2 and NaCl. What volume of Cl_2 will be produced at STP if 50 g of NaCl is taken in the reaction ?

Chlorine gas is prepared by reaction of H_2SO_4 with MnO_2 and NaCl. W

1.	Chlorine gas is prepared by reaction of H_2SO_4 with MnO_2 and NaCl. What volume of Cl_2 will be produced at STP if 50 g of NaCl is taken in the reaction ?
Answer» 1.915 L 22.4 L 11.2 L 9.57 L Solution :`2NaCl+MnO_2 + 3H_2SO_4 to 2NaHSO_4 + MnSO_4 + Cl_2 + 2H_2O` `{:("2 moles","1 MOLE"),("(2 X 58.5 = 117 G )", "22.4 L (STP)"):}` 117g of NaCl `-= 22.4L " of " Cl_2` 50g of NaCl`-=(22.4)/(117)xx50=9.57 L " of " Cl_2` at STP