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Chlorine is prepared in the laboratory by treating manganese dioxide (MnO_(2)) with aqueous hydrochloric acid according to the reaction.4HCl_((aq))+MnO_(2)rarr2H_(2)O+MnCl_(2_((aq)))+Cl_(2_((aq)))How many grams of HCI react with 5.0 g of manganese dioxide ?Atomic mass of Mn = 55 g). |
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Answer» Solution :1 MOLE of `MnO_(2)` = 55 + 32 =87 g. 87g of `MnO_(2)` reacts with 4 MOLES of HCI. i.e. = 4 `xx` 36.5 = 146 g of HCI. `:.` 5 g of `MnO_(2)` will react with`146/87 xx` 5.0 = 8.40 g . |
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