Chlorine is prepared in the laboratory by treating manganese dioxide (MnO_2) with aqueous hydrochloric acid according to the reaction: 4HCl(aq) + MnO_(2)(s) to 2H_(2)O(l) + MnCl_(2)(aq) + Cl_(2)(g). How many grams of HCI react with 5.0g of manganese dioxide?

Chlorine is prepared in the laboratory by treating manganese dioxide (

1.	Chlorine is prepared in the laboratory by treating manganese dioxide (MnO_2) with aqueous hydrochloric acid according to the reaction: 4HCl(aq) + MnO_(2)(s) to 2H_(2)O(l) + MnCl_(2)(aq) + Cl_(2)(g). How many grams of HCI react with 5.0g of manganese dioxide?
Answer» Solution :The GIVEN reaction is: `underset("4 moles " 4 xx 36.5 = 146 g)(4HCL(aq)) + underset("1 mole " 55 + 32 = 87 g)(MnO_(2)(s)) to 2H_(2)O(l) + MnCl_(2)(aq) + Cl_(2)(g)` `therefore 87 g` of `MnO_(2)`react with HCI = 146 g `therefore 5.0 g` of `MnO_(2)` will react with HCI = `146/87 xx 5.0 = 8.39 g`