Chloroform is passed from methane according to the reaction : CH_(4)(g) + 3Cl_(2)(g) rarr CHCl_(3)(l) + 3HCl(g) Calculate Delta Hfor the reaction given that enthalpies of formation of HCl(g), CH_(4)(g)and CHCl_(3)(g) are - 92.0 ,-74.9 and -134.3kJ per mole respectively.

Chloroform is passed from methane according to the reaction : CH_(4)(g

1.	Chloroform is passed from methane according to the reaction : CH_(4)(g) + 3Cl_(2)(g) rarr CHCl_(3)(l) + 3HCl(g) Calculate Delta Hfor the reaction given that enthalpies of formation of HCl(g), CH_(4)(g)and CHCl_(3)(g) are - 92.0 ,-74.9 and -134.3kJ per mole respectively.
Answer» Solution :`Delta_(r) H^(@) = [ Delta_(r) H^(@)(CHCl_(3)) + 3Delta_(f)H^(@) (HCl) ]- [ Delta_(f)H^(@)(CH_(4)) + 3Delta_(f) H^(@) (Cl_(2))]` `[ ( - 134.3) + 3 (-92.0 ) ]-[( - 74.9 ) + 0]` ` = - 335.4kJ MOL^(-1)`