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Choose correct statements (s) regarding the following reactions. `Cr_(2)O_(7)^(2-)(aq)+3SO_(3)^(2-)(aq)+8H^(+) rarr 2Cr^(3+)(aq)+3SO_(4)^(2-)(aq)+4H_(2)O`A. `Cr_(2)O_(7(aq))^(2-)+3SO_(2(g))+2H_((aq))^(+)rarr 2Cr_((aq))^(3+) rarr 2Cr_((aq))^(3+)+3SO_(4(aq))^(2-)+H_(2)O_((l))`B. `2Cr_(2)O_(7(aq))^(2-)+3SO_(2(g))+4H_((aq))^(+)rarr 4Cr_((aq))^(3+)+3SO_(4(aq))^(2-)+2H_(2)O_((l))`C. `Cr_(2)O_(7(aq))^(2-)+3SO_(2(g))+14H_((aq))^(+)rarr 2Cr_((aq))^(3+)+3SO_(4(aq))^(2-)+7H_(2)O_((l))`D. `Cr_(2)O_(7(aq))^(2-)+6SO_(2(g))+7H_((aq))^(+)rarr 2Cr_((aq))^(3+)+6SO_(4(aq))^(2-)+7H_(2)O_((l))` |
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Answer» Correct Answer - A `Cr_(2)O_(7)^(2-)+SO_(2)rarrCr^(3+)+SO_(4)^(2-)` ( in acidic solution) Oxidation half equation : `SO_(2)+2H_(2)O rarr SO_(4)^(2-)+4H^(+)+2e^(-)` ...(i) Reduction half equation : `Cr_(2)O_(7)^(2-)+14H^(+)+6e^(-)rarr 2 Cr^(3+)+7H_(2)O` ...(ii) Multiplying eqn. (i) by 3 and adding to eqn. (ii) we get `Cr_(2)O_(7)^(2-)+3SO_(2)+2H^(+) rarr 2 Cr^(3+)+3SO_(4)^(2-)+H_(2)O` |
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